Base | Representation |
---|---|
bin | 10100000011110111010101… |
… | …00010110010101110111011 |
3 | 12210012012000011211001012111 |
4 | 22001323222202302232323 |
5 | 21240222413233303123 |
6 | 233453202531553151 |
7 | 12202035302506000 |
oct | 1201735242625673 |
9 | 183165004731174 |
10 | 44113249119163 |
11 | 130683621090a4 |
12 | 4b45539a5b7b7 |
13 | 1b7cb27a690c3 |
14 | ac71423318a7 |
15 | 51774817190d |
hex | 281eea8b2bbb |
44113249119163 has 16 divisors (see below), whose sum is σ = 51611592524800. Its totient is φ = 37688192270568.
The previous prime is 44113249119151. The next prime is 44113249119197. The reversal of 44113249119163 is 36191194231144.
It is not a de Polignac number, because 44113249119163 - 237 = 43975810165691 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (49).
It is not an unprimeable number, because it can be changed into a prime (44113249119143) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 209357331 + ... + 209567932.
It is an arithmetic number, because the mean of its divisors is an integer number (3225724532800).
Almost surely, 244113249119163 is an apocalyptic number.
44113249119163 is a deficient number, since it is larger than the sum of its proper divisors (7498343405637).
44113249119163 is an equidigital number, since it uses as much as digits as its factorization.
44113249119163 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 418925591 (or 418925577 counting only the distinct ones).
The product of its digits is 559872, while the sum is 49.
The spelling of 44113249119163 in words is "forty-four trillion, one hundred thirteen billion, two hundred forty-nine million, one hundred nineteen thousand, one hundred sixty-three".
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