Base | Representation |
---|---|
bin | 100000001111011100101… |
… | …1011101000110001101001 |
3 | 120200121202111112212012102 |
4 | 1000132321123220301221 |
5 | 1040100120402441131 |
6 | 13231401520423145 |
7 | 635100551120000 |
oct | 100367133506151 |
9 | 16617674485172 |
10 | 4431222312041 |
11 | 14592a8523138 |
12 | 5b6973477ab5 |
13 | 261b29b05c15 |
14 | 114688007c37 |
15 | 7a3ed9741cb |
hex | 407b96e8c69 |
4431222312041 has 40 divisors (see below), whose sum is σ = 5243492167200. Its totient is φ = 3743996315136.
The previous prime is 4431222311969. The next prime is 4431222312043. The reversal of 4431222312041 is 1402132221344.
It is a de Polignac number, because none of the positive numbers 2k-4431222312041 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 4431222311995 and 4431222312013.
It is not an unprimeable number, because it can be changed into a prime (4431222312043) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 89453306 + ... + 89502828.
It is an arithmetic number, because the mean of its divisors is an integer number (131087304180).
Almost surely, 24431222312041 is an apocalyptic number.
It is an amenable number.
4431222312041 is a deficient number, since it is larger than the sum of its proper divisors (812269855159).
4431222312041 is an frugal number, since it uses more digits than its factorization.
4431222312041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50083 (or 50062 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 4431222312041 its reverse (1402132221344), we get a palindrome (5833354533385).
The spelling of 4431222312041 in words is "four trillion, four hundred thirty-one billion, two hundred twenty-two million, three hundred twelve thousand, forty-one".
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