Base | Representation |
---|---|
bin | 100000111110100001101… |
… | …1010000100010011100011 |
3 | 121001021201021022212100120 |
4 | 1001331003122010103203 |
5 | 1043224143234413011 |
6 | 13350041505051323 |
7 | 645310102200423 |
oct | 101750332042343 |
9 | 17037637285316 |
10 | 4532321404131 |
11 | 1498168303404 |
12 | 612489326b43 |
13 | 26b51c238cc1 |
14 | 11951900c483 |
15 | 7cd69415a06 |
hex | 41f436844e3 |
4532321404131 has 16 divisors (see below), whose sum is σ = 6191734929408. Its totient is φ = 2947257435200.
The previous prime is 4532321404111. The next prime is 4532321404151. The reversal of 4532321404131 is 1314041232354.
4532321404131 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (4532321404111) and next prime (4532321404151).
It is a cyclic number.
It is not a de Polignac number, because 4532321404131 - 25 = 4532321404099 is a prime.
It is a super-2 number, since 2×45323214041312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4532321404092 and 4532321404101.
It is not an unprimeable number, because it can be changed into a prime (4532321404111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3098355 + ... + 4320236.
It is an arithmetic number, because the mean of its divisors is an integer number (386983433088).
Almost surely, 24532321404131 is an apocalyptic number.
4532321404131 is a gapful number since it is divisible by the number (41) formed by its first and last digit.
4532321404131 is a deficient number, since it is larger than the sum of its proper divisors (1659413525277).
4532321404131 is a wasteful number, since it uses less digits than its factorization.
4532321404131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7423602.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 4532321404131 its reverse (1314041232354), we get a palindrome (5846362636485).
The spelling of 4532321404131 in words is "four trillion, five hundred thirty-two billion, three hundred twenty-one million, four hundred four thousand, one hundred thirty-one".
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