Base | Representation |
---|---|
bin | 110111000010011100111011… |
… | …1110000010001110100101011 |
3 | 2100111010121211211020200112222 |
4 | 1232010321313300101310223 |
5 | 1001423324112000041042 |
6 | 4433350345411424255 |
7 | 203654445521630351 |
oct | 15604716760216453 |
9 | 2314117754220488 |
10 | 484122132815147 |
11 | 130290052a33072 |
12 | 4636a1428b508b |
13 | 17a196a1200048 |
14 | 87798c9c337d1 |
15 | 3ae81dad732d2 |
hex | 1b84e77c11d2b |
484122132815147 has 16 divisors (see below), whose sum is σ = 503392098515712. Its totient is φ = 465080560565760.
The previous prime is 484122132815081. The next prime is 484122132815183. The reversal of 484122132815147 is 741518231221484.
It is a cyclic number.
It is not a de Polignac number, because 484122132815147 - 246 = 413753388637483 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (484122132812147) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 431925053 + ... + 433044449.
It is an arithmetic number, because the mean of its divisors is an integer number (31462006157232).
Almost surely, 2484122132815147 is an apocalyptic number.
484122132815147 is a deficient number, since it is larger than the sum of its proper divisors (19269965700565).
484122132815147 is a wasteful number, since it uses less digits than its factorization.
484122132815147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1221398.
The product of its digits is 3440640, while the sum is 53.
The spelling of 484122132815147 in words is "four hundred eighty-four trillion, one hundred twenty-two billion, one hundred thirty-two million, eight hundred fifteen thousand, one hundred forty-seven".
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