Base | Representation |
---|---|
bin | 100100010000001101101… |
… | …0111001110100111001010 |
3 | 122122100000102201102122201 |
4 | 1020200123113032213022 |
5 | 1123113402002343404 |
6 | 14332552355110414 |
7 | 1022660665603120 |
oct | 110403327164712 |
9 | 18570012642581 |
10 | 4982621137354 |
11 | 165113280a863 |
12 | 6857b98a240a |
13 | 2a1b227505a3 |
14 | 133235645910 |
15 | 89921b5dca4 |
hex | 4881b5ce9ca |
4982621137354 has 32 divisors (see below), whose sum is σ = 8737384366080. Its totient is φ = 2086973946288.
The previous prime is 4982621137349. The next prime is 4982621137367. The reversal of 4982621137354 is 4537311262894.
It is a super-3 number, since 3×49826211373543 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4982621137295 and 4982621137304.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20794114 + ... + 21032365.
It is an arithmetic number, because the mean of its divisors is an integer number (273043261440).
Almost surely, 24982621137354 is an apocalyptic number.
4982621137354 is a deficient number, since it is larger than the sum of its proper divisors (3754763228726).
4982621137354 is a wasteful number, since it uses less digits than its factorization.
4982621137354 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41826682.
The product of its digits is 8709120, while the sum is 55.
The spelling of 4982621137354 in words is "four trillion, nine hundred eighty-two billion, six hundred twenty-one million, one hundred thirty-seven thousand, three hundred fifty-four".
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