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5034313410153 = 397117701146983
BaseRepresentation
bin100100101000010010001…
…1101100110011001101001
3122211021102221211222010220
41021100210131212121221
51124440233213111103
614412422012000253
71026500656635606
oct111204435463151
918737387758126
105034313410153
111671049748475
12693825460089
132a696cc92661
1413593aa096ad
158ae49d7cc53
hex49424766669

5034313410153 has 16 divisors (see below), whose sum is σ = 6781721821056. Its totient is φ = 3321558028800.

The previous prime is 5034313410151. The next prime is 5034313410229. The reversal of 5034313410153 is 3510143134305.

It is not a de Polignac number, because 5034313410153 - 21 = 5034313410151 is a prime.

It is not an unprimeable number, because it can be changed into a prime (5034313410151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34177500 + ... + 34324482.

It is an arithmetic number, because the mean of its divisors is an integer number (423857613816).

Almost surely, 25034313410153 is an apocalyptic number.

It is an amenable number.

5034313410153 is a deficient number, since it is larger than the sum of its proper divisors (1747408410903).

5034313410153 is a wasteful number, since it uses less digits than its factorization.

5034313410153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 264784.

The product of its (nonzero) digits is 32400, while the sum is 33.

Adding to 5034313410153 its reverse (3510143134305), we get a palindrome (8544456544458).

The spelling of 5034313410153 in words is "five trillion, thirty-four billion, three hundred thirteen million, four hundred ten thousand, one hundred fifty-three".

Divisors: 1 3 97 291 117701 146983 353103 440949 11416997 14257351 34250991 42772053 17300046083 51900138249 1678104470051 5034313410153