Base | Representation |
---|---|
bin | 101110111101010110… |
… | …100000010010111011 |
3 | 11211010221211012202011 |
4 | 232331112200102323 |
5 | 1311230341333111 |
6 | 35055134150351 |
7 | 3433330053640 |
oct | 567526402273 |
9 | 154127735664 |
10 | 50421433531 |
11 | 1a424648327 |
12 | 99320523b7 |
13 | 49a7177091 |
14 | 26246b3dc7 |
15 | 14a188e021 |
hex | bbd5a04bb |
50421433531 has 16 divisors (see below), whose sum is σ = 58188095680. Its totient is φ = 42796149120.
The previous prime is 50421433523. The next prime is 50421433547. The reversal of 50421433531 is 13533412405.
It is a cyclic number.
It is not a de Polignac number, because 50421433531 - 23 = 50421433523 is a prime.
It is a super-2 number, since 2×504214335312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 50421433493 and 50421433502.
It is not an unprimeable number, because it can be changed into a prime (50421433591) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1309405 + ... + 1347361.
It is an arithmetic number, because the mean of its divisors is an integer number (3636755980).
Almost surely, 250421433531 is an apocalyptic number.
50421433531 is a deficient number, since it is larger than the sum of its proper divisors (7766662149).
50421433531 is a wasteful number, since it uses less digits than its factorization.
50421433531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39814.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 50421433531 its reverse (13533412405), we get a palindrome (63954845936).
The spelling of 50421433531 in words is "fifty billion, four hundred twenty-one million, four hundred thirty-three thousand, five hundred thirty-one".
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