Base | Representation |
---|---|
bin | 100100110001100110010… |
… | …0010000000000101011011 |
3 | 122220012001202121200011220 |
4 | 1021203030202000011123 |
5 | 1130302213112133103 |
6 | 14425530324423123 |
7 | 1031106405455514 |
oct | 111431442000533 |
9 | 18805052550156 |
10 | 5054313005403 |
11 | 1679581a20392 |
12 | 697687247aa3 |
13 | 2a8809557c9c |
14 | 1368b6c27a0b |
15 | 8b71aa68c53 |
hex | 498cc88015b |
5054313005403 has 16 divisors (see below), whose sum is σ = 6989442911232. Its totient is φ = 3245392836000.
The previous prime is 5054313005387. The next prime is 5054313005447. The reversal of 5054313005403 is 3045003134505.
It is not a de Polignac number, because 5054313005403 - 24 = 5054313005387 is a prime.
It is a super-3 number, since 3×50543130054033 (a number of 39 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (5054313005003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 128765808 + ... + 128805053.
It is an arithmetic number, because the mean of its divisors is an integer number (436840181952).
Almost surely, 25054313005403 is an apocalyptic number.
5054313005403 is a deficient number, since it is larger than the sum of its proper divisors (1935129905829).
5054313005403 is a wasteful number, since it uses less digits than its factorization.
5054313005403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 257571106.
The product of its (nonzero) digits is 54000, while the sum is 33.
Adding to 5054313005403 its reverse (3045003134505), we get a palindrome (8099316139908).
The spelling of 5054313005403 in words is "five trillion, fifty-four billion, three hundred thirteen million, five thousand, four hundred three".
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