Base | Representation |
---|---|
bin | 111001111111000011010001… |
… | …1110101111101001000011010 |
3 | 2110212220122010122010221022220 |
4 | 1303332012203311331020122 |
5 | 1013323021031013211442 |
6 | 5004434304120524510 |
7 | 212301251005525662 |
oct | 16376064365751032 |
9 | 2425818118127286 |
10 | 510043000132122 |
11 | 138574026865566 |
12 | 49255900920736 |
13 | 18b79b05301172 |
14 | 8dd42da3951a2 |
15 | 3de75c78e5eec |
hex | 1cfe1a3d7d21a |
510043000132122 has 32 divisors (see below), whose sum is σ = 1065678650910720. Its totient is φ = 162547710880560.
The previous prime is 510043000132111. The next prime is 510043000132147. The reversal of 510043000132122 is 221231000340015.
It is a junction number, because it is equal to n+sod(n) for n = 510043000132092 and 510043000132101.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16519060872 + ... + 16519091747.
It is an arithmetic number, because the mean of its divisors is an integer number (33302457840960).
Almost surely, 2510043000132122 is an apocalyptic number.
510043000132122 is an abundant number, since it is smaller than the sum of its proper divisors (555635650778598).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
510043000132122 is a wasteful number, since it uses less digits than its factorization.
510043000132122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33038152738.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 510043000132122 its reverse (221231000340015), we get a palindrome (731274000472137).
The spelling of 510043000132122 in words is "five hundred ten trillion, forty-three billion, one hundred thirty-two thousand, one hundred twenty-two".
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