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5113002422234 = 273162711547553
BaseRepresentation
bin100101001100111011010…
…1100010110111111011010
3200002210112221002221210202
41022121312230112333122
51132232412110002414
614512514134342202
71035254652334160
oct112316654267732
920083487087722
105113002422234
1116a1459631963
126a6b261ba962
132b1200613075
14139683603230
158d0031da9de
hex4a676b16fda

5113002422234 has 16 divisors (see below), whose sum is σ = 8765424909888. Its totient is φ = 2191217277312.

The previous prime is 5113002422167. The next prime is 5113002422251. The reversal of 5113002422234 is 4322242003115.

It is a super-2 number, since 2×51130024222342 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5113002422197 and 5113002422206.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5330999 + ... + 6216554.

It is an arithmetic number, because the mean of its divisors is an integer number (547839056868).

Almost surely, 25113002422234 is an apocalyptic number.

5113002422234 is a deficient number, since it is larger than the sum of its proper divisors (3652422487654).

5113002422234 is a wasteful number, since it uses less digits than its factorization.

5113002422234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11579189.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 5113002422234 its reverse (4322242003115), we get a palindrome (9435244425349).

The spelling of 5113002422234 in words is "five trillion, one hundred thirteen billion, two million, four hundred twenty-two thousand, two hundred thirty-four".

Divisors: 1 2 7 14 31627 63254 221389 442778 11547553 23095106 80832871 161665742 365214458731 730428917462 2556501211117 5113002422234