Base | Representation |
---|---|
bin | 100101001100111111100… |
… | …0010101110101001101011 |
3 | 200002210220200200211220220 |
4 | 1022121333002232221223 |
5 | 1132233203440112133 |
6 | 14512540101021123 |
7 | 1035261303115020 |
oct | 112317702565153 |
9 | 20083820624826 |
10 | 5113142504043 |
11 | 16a152070a452 |
12 | 6a6b650b47a3 |
13 | 2b122364b702 |
14 | 139698069547 |
15 | 8d01065b5b3 |
hex | 4a67f0aea6b |
5113142504043 has 48 divisors (see below), whose sum is σ = 7946304687360. Its totient is φ = 2864817624960.
The previous prime is 5113142504033. The next prime is 5113142504077. The reversal of 5113142504043 is 3404052413115.
It is not a de Polignac number, because 5113142504043 - 24 = 5113142504027 is a prime.
It is a super-2 number, since 2×51131425040432 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5113142503995 and 5113142504013.
It is not an unprimeable number, because it can be changed into a prime (5113142504033) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 24667488 + ... + 24873906.
It is an arithmetic number, because the mean of its divisors is an integer number (165548014320).
Almost surely, 25113142504043 is an apocalyptic number.
5113142504043 is a deficient number, since it is larger than the sum of its proper divisors (2833162183317).
5113142504043 is a wasteful number, since it uses less digits than its factorization.
5113142504043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 206868 (or 206807 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 5113142504043 its reverse (3404052413115), we get a palindrome (8517194917158).
The spelling of 5113142504043 in words is "five trillion, one hundred thirteen billion, one hundred forty-two million, five hundred four thousand, forty-three".
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