Base | Representation |
---|---|
bin | 1110111000011100100… |
… | …00110111100001111001 |
3 | 1210212212012012021120210 |
4 | 13130032100313201321 |
5 | 31334211121123001 |
6 | 1030523451341333 |
7 | 51641330531160 |
oct | 7341620674171 |
9 | 1725765167523 |
10 | 511340411001 |
11 | 1879493710a2 |
12 | 83126a51849 |
13 | 392b0751b44 |
14 | 1aa6b3c63d7 |
15 | d47b514dd6 |
hex | 770e437879 |
511340411001 has 16 divisors (see below), whose sum is σ = 784148357504. Its totient is φ = 290333407104.
The previous prime is 511340410991. The next prime is 511340411017. The reversal of 511340411001 is 100114043115.
It is not a de Polignac number, because 511340411001 - 26 = 511340410937 is a prime.
It is a super-2 number, since 2×5113404110012 (a number of 24 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (511340411501) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 77543020 + ... + 77549613.
It is an arithmetic number, because the mean of its divisors is an integer number (49009272344).
Almost surely, 2511340411001 is an apocalyptic number.
It is an amenable number.
511340411001 is a deficient number, since it is larger than the sum of its proper divisors (272807946503).
511340411001 is a wasteful number, since it uses less digits than its factorization.
511340411001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 155092800.
The product of its (nonzero) digits is 240, while the sum is 21.
Adding to 511340411001 its reverse (100114043115), we get a palindrome (611454454116).
The spelling of 511340411001 in words is "five hundred eleven billion, three hundred forty million, four hundred eleven thousand, one".
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