Base | Representation |
---|---|
bin | 10111010010011111111000… |
… | …10101100100111000011011 |
3 | 20201022221000222121120200020 |
4 | 23221033330111210320123 |
5 | 23203033441404202411 |
6 | 300530553025041523 |
7 | 13534012032306321 |
oct | 1351177425447033 |
9 | 221287028546606 |
10 | 51213128584731 |
11 | 15355402a65203 |
12 | 58b15451862a3 |
13 | 22764b9c20bc9 |
14 | c90a2b5add11 |
15 | 5dc2871eb606 |
hex | 2e93fc564e1b |
51213128584731 has 32 divisors (see below), whose sum is σ = 72150558105600. Its totient is φ = 32222540547360.
The previous prime is 51213128584721. The next prime is 51213128584759. The reversal of 51213128584731 is 13748582131215.
It is not a de Polignac number, because 51213128584731 - 222 = 51213124390427 is a prime.
It is a super-2 number, since 2×512131285847312 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (51213128584721) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 158432890 + ... + 158755808.
It is an arithmetic number, because the mean of its divisors is an integer number (2254704940800).
Almost surely, 251213128584731 is an apocalyptic number.
51213128584731 is a deficient number, since it is larger than the sum of its proper divisors (20937429520869).
51213128584731 is a wasteful number, since it uses less digits than its factorization.
51213128584731 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 333479.
The product of its digits is 1612800, while the sum is 51.
The spelling of 51213128584731 in words is "fifty-one trillion, two hundred thirteen billion, one hundred twenty-eight million, five hundred eighty-four thousand, seven hundred thirty-one".
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