Base | Representation |
---|---|
bin | 111010010111110001010010… |
… | …0110010100010001000001001 |
3 | 2111022221102020202100010120001 |
4 | 1310233202210302202020021 |
5 | 1014244201301244042213 |
6 | 5015555122252403001 |
7 | 213101561100620545 |
oct | 16457424462421011 |
9 | 2438842222303501 |
10 | 513440335143433 |
11 | 139663906910145 |
12 | 49704215476461 |
13 | 190652a62c38c9 |
14 | 90b0905532a25 |
15 | 3e55b64ab71dd |
hex | 1d2f8a4ca2209 |
513440335143433 has 16 divisors (see below), whose sum is σ = 531354370305600. Its totient is φ = 495540284747200.
The previous prime is 513440335143431. The next prime is 513440335143499. The reversal of 513440335143433 is 334341533044315.
It is a cyclic number.
It is not a de Polignac number, because 513440335143433 - 21 = 513440335143431 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (513440335143431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 760552803 + ... + 761227591.
It is an arithmetic number, because the mean of its divisors is an integer number (33209648144100).
Almost surely, 2513440335143433 is an apocalyptic number.
It is an amenable number.
513440335143433 is a deficient number, since it is larger than the sum of its proper divisors (17914035162167).
513440335143433 is a wasteful number, since it uses less digits than its factorization.
513440335143433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 685112.
The product of its (nonzero) digits is 4665600, while the sum is 46.
Adding to 513440335143433 its reverse (334341533044315), we get a palindrome (847781868187748).
The spelling of 513440335143433 in words is "five hundred thirteen trillion, four hundred forty billion, three hundred thirty-five million, one hundred forty-three thousand, four hundred thirty-three".
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