Base | Representation |
---|---|
bin | 111010011100000101010111… |
… | …0111101101000100001110001 |
3 | 2111102001002120022110001210120 |
4 | 1310320022232331220201301 |
5 | 1014333410004043442431 |
6 | 5021131333002320453 |
7 | 213162450112120455 |
oct | 16470125675504161 |
9 | 2442032508401716 |
10 | 514033211312241 |
11 | 139872295a70945 |
12 | 4979b0b64b9129 |
13 | 190a917c0ac48a |
14 | 90d14a9624665 |
15 | 3e662b430a196 |
hex | 1d382aef68871 |
514033211312241 has 16 divisors (see below), whose sum is σ = 685543578071040. Its totient is φ = 342605828313680.
The previous prime is 514033211312221. The next prime is 514033211312273. The reversal of 514033211312241 is 142213112330415.
It is a cyclic number.
It is not a de Polignac number, because 514033211312241 - 215 = 514033211279473 is a prime.
It is not an unprimeable number, because it can be changed into a prime (514033211312221) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1068340066 + ... + 1068821108.
It is an arithmetic number, because the mean of its divisors is an integer number (42846473629440).
Almost surely, 2514033211312241 is an apocalyptic number.
It is an amenable number.
514033211312241 is a deficient number, since it is larger than the sum of its proper divisors (171510366758799).
514033211312241 is a wasteful number, since it uses less digits than its factorization.
514033211312241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 566556.
The product of its (nonzero) digits is 17280, while the sum is 33.
Adding to 514033211312241 its reverse (142213112330415), we get a palindrome (656246323642656).
The spelling of 514033211312241 in words is "five hundred fourteen trillion, thirty-three billion, two hundred eleven million, three hundred twelve thousand, two hundred forty-one".
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