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514033211312241 = 3439181119481043
BaseRepresentation
bin111010011100000101010111…
…0111101101000100001110001
32111102001002120022110001210120
41310320022232331220201301
51014333410004043442431
65021131333002320453
7213162450112120455
oct16470125675504161
92442032508401716
10514033211312241
11139872295a70945
124979b0b64b9129
13190a917c0ac48a
1490d14a9624665
153e662b430a196
hex1d382aef68871

514033211312241 has 16 divisors (see below), whose sum is σ = 685543578071040. Its totient is φ = 342605828313680.

The previous prime is 514033211312221. The next prime is 514033211312273. The reversal of 514033211312241 is 142213112330415.

It is a cyclic number.

It is not a de Polignac number, because 514033211312241 - 215 = 514033211279473 is a prime.

It is not an unprimeable number, because it can be changed into a prime (514033211312221) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1068340066 + ... + 1068821108.

It is an arithmetic number, because the mean of its divisors is an integer number (42846473629440).

Almost surely, 2514033211312241 is an apocalyptic number.

It is an amenable number.

514033211312241 is a deficient number, since it is larger than the sum of its proper divisors (171510366758799).

514033211312241 is a wasteful number, since it uses less digits than its factorization.

514033211312241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 566556.

The product of its (nonzero) digits is 17280, while the sum is 33.

Adding to 514033211312241 its reverse (142213112330415), we get a palindrome (656246323642656).

The spelling of 514033211312241 in words is "five hundred fourteen trillion, thirty-three billion, two hundred eleven million, three hundred twelve thousand, two hundred forty-one".

Divisors: 1 3 4391 13173 81119 243357 481043 1443129 356193529 1068580587 2112259813 6336779439 39021727117 117065181351 171344403770747 514033211312241