Base | Representation |
---|---|
bin | 100101011111100011011… |
… | …1000101101010000101001 |
3 | 200020121210121101120202111 |
4 | 1022333012320231100221 |
5 | 1133411322122321441 |
6 | 14543131240002321 |
7 | 1041202130624410 |
oct | 112770670552051 |
9 | 20217717346674 |
10 | 5153002542121 |
11 | 1707415661a85 |
12 | 6b282a1603a1 |
13 | 2b4c06708065 |
14 | 13b599c02477 |
15 | 8e094be8081 |
hex | 4afc6e2d429 |
5153002542121 has 32 divisors (see below), whose sum is σ = 5936837898240. Its totient is φ = 4381228153536.
The previous prime is 5153002542031. The next prime is 5153002542131. The reversal of 5153002542121 is 1212452003515.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5153002542121 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5153002542131) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1037445180 + ... + 1037450146.
It is an arithmetic number, because the mean of its divisors is an integer number (185526184320).
Almost surely, 25153002542121 is an apocalyptic number.
It is an amenable number.
5153002542121 is a deficient number, since it is larger than the sum of its proper divisors (783835356119).
5153002542121 is a wasteful number, since it uses less digits than its factorization.
5153002542121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7053.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 5153002542121 its reverse (1212452003515), we get a palindrome (6365454545636).
The spelling of 5153002542121 in words is "five trillion, one hundred fifty-three billion, two million, five hundred forty-two thousand, one hundred twenty-one".
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