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51542254024113 = 3197395692204047
BaseRepresentation
bin10111011100000100111011…
…01111011111010110110001
320202111101120022012020011110
423232002131233133112301
523223432014012232423
6301342103513303533
713566543050344266
oct1356023557372661
9222441508166143
1051542254024113
1115471a46769166
125945298704ba9
13229b54bb873c8
14ca293094326d
155e5aeb830193
hex2ee09dbdf5b1

51542254024113 has 16 divisors (see below), whose sum is σ = 69073630053120. Its totient is φ = 34186199314176.

The previous prime is 51542254024097. The next prime is 51542254024117. The reversal of 51542254024113 is 31142045224515.

It is not a de Polignac number, because 51542254024113 - 24 = 51542254024097 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (51542254024117) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22283256 + ... + 24487302.

It is an arithmetic number, because the mean of its divisors is an integer number (4317101878320).

Almost surely, 251542254024113 is an apocalyptic number.

It is an amenable number.

51542254024113 is a deficient number, since it is larger than the sum of its proper divisors (17531376029007).

51542254024113 is a wasteful number, since it uses less digits than its factorization.

51542254024113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2243816.

The product of its (nonzero) digits is 192000, while the sum is 39.

Adding to 51542254024113 its reverse (31142045224515), we get a palindrome (82684299248628).

The spelling of 51542254024113 in words is "fifty-one trillion, five hundred forty-two billion, two hundred fifty-four million, twenty-four thousand, one hundred thirteen".

Divisors: 1 3 197 591 39569 118707 2204047 6612141 7795093 23385279 434197259 1302591777 87211935743 261635807229 17180751341371 51542254024113