Base | Representation |
---|---|
bin | 10111011100000100111011… |
… | …01111011111010110110001 |
3 | 20202111101120022012020011110 |
4 | 23232002131233133112301 |
5 | 23223432014012232423 |
6 | 301342103513303533 |
7 | 13566543050344266 |
oct | 1356023557372661 |
9 | 222441508166143 |
10 | 51542254024113 |
11 | 15471a46769166 |
12 | 5945298704ba9 |
13 | 229b54bb873c8 |
14 | ca293094326d |
15 | 5e5aeb830193 |
hex | 2ee09dbdf5b1 |
51542254024113 has 16 divisors (see below), whose sum is σ = 69073630053120. Its totient is φ = 34186199314176.
The previous prime is 51542254024097. The next prime is 51542254024117. The reversal of 51542254024113 is 31142045224515.
It is not a de Polignac number, because 51542254024113 - 24 = 51542254024097 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (51542254024117) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22283256 + ... + 24487302.
It is an arithmetic number, because the mean of its divisors is an integer number (4317101878320).
Almost surely, 251542254024113 is an apocalyptic number.
It is an amenable number.
51542254024113 is a deficient number, since it is larger than the sum of its proper divisors (17531376029007).
51542254024113 is a wasteful number, since it uses less digits than its factorization.
51542254024113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2243816.
The product of its (nonzero) digits is 192000, while the sum is 39.
Adding to 51542254024113 its reverse (31142045224515), we get a palindrome (82684299248628).
The spelling of 51542254024113 in words is "fifty-one trillion, five hundred forty-two billion, two hundred fifty-four million, twenty-four thousand, one hundred thirteen".
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