Base | Representation |
---|---|
bin | 100110001000001110010… |
… | …1111111111010010010001 |
3 | 200112222020110211021002211 |
4 | 1030100130233333102101 |
5 | 1141324210131140103 |
6 | 15051214033112121 |
7 | 1050413366551366 |
oct | 114203457772221 |
9 | 20488213737084 |
10 | 5240342443153 |
11 | 174046476a374 |
12 | 7077440b8641 |
13 | 2c02153a437c |
14 | 1418c36d646d |
15 | 914a777236d |
hex | 4c41cbff491 |
5240342443153 has 16 divisors (see below), whose sum is σ = 5453672328000. Its totient is φ = 5029212096832.
The previous prime is 5240342443109. The next prime is 5240342443177. The reversal of 5240342443153 is 3513442430425.
It is a cyclic number.
It is not a de Polignac number, because 5240342443153 - 217 = 5240342312081 is a prime.
It is a super-2 number, since 2×52403424431532 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5240342443183) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11925951 + ... + 12357547.
It is an arithmetic number, because the mean of its divisors is an integer number (340854520500).
Almost surely, 25240342443153 is an apocalyptic number.
It is an amenable number.
5240342443153 is a deficient number, since it is larger than the sum of its proper divisors (213329884847).
5240342443153 is a wasteful number, since it uses less digits than its factorization.
5240342443153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 434144.
The product of its (nonzero) digits is 691200, while the sum is 40.
Adding to 5240342443153 its reverse (3513442430425), we get a palindrome (8753784873578).
The spelling of 5240342443153 in words is "five trillion, two hundred forty billion, three hundred forty-two million, four hundred forty-three thousand, one hundred fifty-three".
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