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5240342443153 = 291792339431597
BaseRepresentation
bin100110001000001110010…
…1111111111010010010001
3200112222020110211021002211
41030100130233333102101
51141324210131140103
615051214033112121
71050413366551366
oct114203457772221
920488213737084
105240342443153
11174046476a374
127077440b8641
132c02153a437c
141418c36d646d
15914a777236d
hex4c41cbff491

5240342443153 has 16 divisors (see below), whose sum is σ = 5453672328000. Its totient is φ = 5029212096832.

The previous prime is 5240342443109. The next prime is 5240342443177. The reversal of 5240342443153 is 3513442430425.

It is a cyclic number.

It is not a de Polignac number, because 5240342443153 - 217 = 5240342312081 is a prime.

It is a super-2 number, since 2×52403424431532 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5240342443183) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11925951 + ... + 12357547.

It is an arithmetic number, because the mean of its divisors is an integer number (340854520500).

Almost surely, 25240342443153 is an apocalyptic number.

It is an amenable number.

5240342443153 is a deficient number, since it is larger than the sum of its proper divisors (213329884847).

5240342443153 is a wasteful number, since it uses less digits than its factorization.

5240342443153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 434144.

The product of its (nonzero) digits is 691200, while the sum is 40.

Adding to 5240342443153 its reverse (3513442430425), we get a palindrome (8753784873578).

The spelling of 5240342443153 in words is "five trillion, two hundred forty billion, three hundred forty-two million, four hundred forty-three thousand, one hundred fifty-three".

Divisors: 1 29 179 2339 5191 67831 418681 431597 12141749 12516313 77255863 1009505383 2240420027 29275656107 180701463557 5240342443153