Base | Representation |
---|---|
bin | 110000111010100001… |
… | …101000101011001001 |
3 | 12000120022110211001220 |
4 | 300322201220223021 |
5 | 1330031001102213 |
6 | 40043354032253 |
7 | 3536350261500 |
oct | 607241505311 |
9 | 160508424056 |
10 | 52521503433 |
11 | 20302023993 |
12 | a219418689 |
13 | 4c5028a9a9 |
14 | 278357b837 |
15 | 1575e1be23 |
hex | c3a868ac9 |
52521503433 has 48 divisors (see below), whose sum is σ = 83326970304. Its totient is φ = 29331469440.
The previous prime is 52521503431. The next prime is 52521503509. The reversal of 52521503433 is 33430512525.
It is not a de Polignac number, because 52521503433 - 21 = 52521503431 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 52521503394 and 52521503403.
It is not an unprimeable number, because it can be changed into a prime (52521503431) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1389166 + ... + 1426472.
It is an arithmetic number, because the mean of its divisors is an integer number (1735978548).
Almost surely, 252521503433 is an apocalyptic number.
It is an amenable number.
52521503433 is a deficient number, since it is larger than the sum of its proper divisors (30805466871).
52521503433 is a wasteful number, since it uses less digits than its factorization.
52521503433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37542 (or 37535 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 33.
The spelling of 52521503433 in words is "fifty-two billion, five hundred twenty-one million, five hundred three thousand, four hundred thirty-three".
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