Base | Representation |
---|---|
bin | 110001010111101110… |
… | …100110111010011010 |
3 | 12001211110101100021220 |
4 | 301113232212322122 |
5 | 1332031412141404 |
6 | 40204135112510 |
7 | 3554446555662 |
oct | 612756467232 |
9 | 161743340256 |
10 | 53011443354 |
11 | 2053363a011 |
12 | a335512736 |
13 | 4cca92ca7c |
14 | 27cc6751a2 |
15 | 15a3e494d9 |
hex | c57ba6e9a |
53011443354 has 64 divisors (see below), whose sum is σ = 112675829760. Its totient is φ = 16580108160.
The previous prime is 53011443347. The next prime is 53011443361. The reversal of 53011443354 is 45334411035.
It is an interprime number because it is at equal distance from previous prime (53011443347) and next prime (53011443361).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7227469 + ... + 7234799.
It is an arithmetic number, because the mean of its divisors is an integer number (1760559840).
Almost surely, 253011443354 is an apocalyptic number.
53011443354 is an abundant number, since it is smaller than the sum of its proper divisors (59664386406).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53011443354 is a wasteful number, since it uses less digits than its factorization.
53011443354 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7955.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 53011443354 its reverse (45334411035), we get a palindrome (98345854389).
The spelling of 53011443354 in words is "fifty-three billion, eleven million, four hundred forty-three thousand, three hundred fifty-four".
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