Base | Representation |
---|---|
bin | 110001011000110111… |
… | …010100101000101011 |
3 | 12001212210020202221220 |
4 | 301120313110220223 |
5 | 1332101302130003 |
6 | 40210055433123 |
7 | 3555100566210 |
oct | 613067245053 |
9 | 161783222856 |
10 | 53030505003 |
11 | 20543379343 |
12 | a33b9857a3 |
13 | 5001875058 |
14 | 27d0dd7b07 |
15 | 15a5962353 |
hex | c58dd4a2b |
53030505003 has 16 divisors (see below), whose sum is σ = 81275494656. Its totient is φ = 30127980960.
The previous prime is 53030504959. The next prime is 53030505029. The reversal of 53030505003 is 30050503035.
53030505003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53030505003 - 210 = 53030503979 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53030505053) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7294813 + ... + 7302078.
It is an arithmetic number, because the mean of its divisors is an integer number (5079718416).
Almost surely, 253030505003 is an apocalyptic number.
53030505003 is a deficient number, since it is larger than the sum of its proper divisors (28244989653).
53030505003 is a wasteful number, since it uses less digits than its factorization.
53030505003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14597074.
The product of its (nonzero) digits is 3375, while the sum is 24.
The spelling of 53030505003 in words is "fifty-three billion, thirty million, five hundred five thousand, three".
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