Base | Representation |
---|---|
bin | 111100010011010110100010… |
… | …0111101011110000100001001 |
3 | 2120120002011110202122011120012 |
4 | 1320212231010331132010021 |
5 | 1024010442030200201241 |
6 | 5120042010210041305 |
7 | 216503651660012663 |
oct | 17046550475360411 |
9 | 2516064422564505 |
10 | 530425323053321 |
11 | 144012130781a63 |
12 | 4b5a7b93579235 |
13 | 199c7b7c887697 |
14 | 94daa18c07533 |
15 | 414c8a73076eb |
hex | 1e26b44f5e109 |
530425323053321 has 16 divisors (see below), whose sum is σ = 561583416461760. Its totient is φ = 500129595309120.
The previous prime is 530425323053299. The next prime is 530425323053387. The reversal of 530425323053321 is 123350323524035.
It is a cyclic number.
It is not a de Polignac number, because 530425323053321 - 222 = 530425318859017 is a prime.
It is a super-3 number, since 3×5304253230533213 (a number of 45 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530425323053621) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33865415 + ... + 46986348.
It is an arithmetic number, because the mean of its divisors is an integer number (35098963528860).
Almost surely, 2530425323053321 is an apocalyptic number.
It is an amenable number.
530425323053321 is a deficient number, since it is larger than the sum of its proper divisors (31158093408439).
530425323053321 is a wasteful number, since it uses less digits than its factorization.
530425323053321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80857096.
The product of its (nonzero) digits is 972000, while the sum is 41.
Adding to 530425323053321 its reverse (123350323524035), we get a palindrome (653775646577356).
The spelling of 530425323053321 in words is "five hundred thirty trillion, four hundred twenty-five billion, three hundred twenty-three million, fifty-three thousand, three hundred twenty-one".
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