Base | Representation |
---|---|
bin | 110001011110010010… |
… | …011010000110100001 |
3 | 12002010010110100210000 |
4 | 301132102122012201 |
5 | 1332243100210421 |
6 | 40223105530213 |
7 | 3560254140441 |
oct | 613622320641 |
9 | 162103410700 |
10 | 53121491361 |
11 | 2058a773784 |
12 | a366343969 |
13 | 5017680c33 |
14 | 27dd120121 |
15 | 15ad936226 |
hex | c5e49a1a1 |
53121491361 has 15 divisors (see below), whose sum is σ = 79357425411. Its totient is φ = 35412944688.
The previous prime is 53121491329. The next prime is 53121491363. The reversal of 53121491361 is 16319412135.
The square root of 53121491361 is 230481.
It is a perfect power (a square), and thus also a powerful number.
53121491361 is a `hidden beast` number, since 531 + 2 + 1 + 4 + 91 + 36 + 1 = 666.
It can be written as a sum of positive squares in only one way, i.e., 53046841761 + 74649600 = 230319^2 + 8640^2 .
It is not a de Polignac number, because 53121491361 - 25 = 53121491329 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53121491363) by changing a digit.
It is a polite number, since it can be written in 14 ways as a sum of consecutive naturals, for example, 2061525 + ... + 2087133.
Almost surely, 253121491361 is an apocalyptic number.
53121491361 is the 230481-st square number.
53121491361 is the 115241-st centered octagonal number.
It is an amenable number.
53121491361 is a deficient number, since it is larger than the sum of its proper divisors (26235934050).
53121491361 is an frugal number, since it uses more digits than its factorization.
53121491361 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51230 (or 25612 counting only the distinct ones).
The product of its digits is 19440, while the sum is 36.
Multiplying 53121491361 by its sum of digits (36), we get a square (1912373688996 = 13828862).
The spelling of 53121491361 in words is "fifty-three billion, one hundred twenty-one million, four hundred ninety-one thousand, three hundred sixty-one".
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