Base | Representation |
---|---|
bin | 100110110100011101111… |
… | …0101101001100100110011 |
3 | 200220001110221111221100220 |
4 | 1031220323311221210303 |
5 | 1144403300421120144 |
6 | 15203005533344123 |
7 | 1060316012535000 |
oct | 115507365514463 |
9 | 20801427457326 |
10 | 5335353301299 |
11 | 177778a93433a |
12 | 72203b038043 |
13 | 2c9177387568 |
14 | 146337cc08a7 |
15 | 93bb899c919 |
hex | 4da3bd69933 |
5335353301299 has 16 divisors (see below), whose sum is σ = 8295981811200. Its totient is φ = 3048773314440.
The previous prime is 5335353301241. The next prime is 5335353301303. The reversal of 5335353301299 is 9921033535335.
5335353301299 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5335353301299 - 28 = 5335353301043 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5335353301219) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2592493287 + ... + 2592495344.
It is an arithmetic number, because the mean of its divisors is an integer number (518498863200).
Almost surely, 25335353301299 is an apocalyptic number.
5335353301299 is a deficient number, since it is larger than the sum of its proper divisors (2960628509901).
5335353301299 is an equidigital number, since it uses as much as digits as its factorization.
5335353301299 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5184988655 (or 5184988641 counting only the distinct ones).
The product of its (nonzero) digits is 4920750, while the sum is 51.
The spelling of 5335353301299 in words is "five trillion, three hundred thirty-five billion, three hundred fifty-three million, three hundred one thousand, two hundred ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •