Base | Representation |
---|---|
bin | 111100110000100110100110… |
… | …0110011100001111001010001 |
3 | 2121002022111100212201011011111 |
4 | 1321201031030303201321101 |
5 | 1030022323433234214403 |
6 | 5132400520554213321 |
7 | 220400262542465641 |
oct | 17141151463417121 |
9 | 2532274325634144 |
10 | 534445544054353 |
11 | 14532209a719a28 |
12 | 4bb37163424241 |
13 | 19c29cc9a88c89 |
14 | 95d943391a521 |
15 | 41bc24d63556d |
hex | 1e6134cce1e51 |
534445544054353 has 16 divisors (see below), whose sum is σ = 565008454183936. Its totient is φ = 504861387217920.
The previous prime is 534445544054321. The next prime is 534445544054393. The reversal of 534445544054353 is 353450445544435.
It is a cyclic number.
It is not a de Polignac number, because 534445544054353 - 25 = 534445544054321 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (534445544054393) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1217135301 + ... + 1217574322.
It is an arithmetic number, because the mean of its divisors is an integer number (35313028386496).
Almost surely, 2534445544054353 is an apocalyptic number.
It is an amenable number.
534445544054353 is a deficient number, since it is larger than the sum of its proper divisors (30562910129583).
534445544054353 is a wasteful number, since it uses less digits than its factorization.
534445544054353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2434709824.
The product of its (nonzero) digits is 345600000, while the sum is 58.
Adding to 534445544054353 its reverse (353450445544435), we get a palindrome (887895989598788).
The spelling of 534445544054353 in words is "five hundred thirty-four trillion, four hundred forty-five billion, five hundred forty-four million, fifty-four thousand, three hundred fifty-three".
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