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540140433 = 3726995617
BaseRepresentation
bin100000001100011…
…110001110010001
31101122100222101020
4200030132032101
52101233443213
6125333030053
716246055310
oct4014361621
91348328336
10540140433
11257993558
12130a85329
1387b9a831
1451a44277
1532646923
hex2031e391

540140433 has 16 divisors (see below), whose sum is σ = 826139520. Its totient is φ = 307501056.

The previous prime is 540140423. The next prime is 540140443. The reversal of 540140433 is 334041045.

It is an interprime number because it is at equal distance from previous prime (540140423) and next prime (540140443).

It is not a de Polignac number, because 540140433 - 26 = 540140369 is a prime.

It is a super-2 number, since 2×5401404332 = 583503374722854978, which contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (540140413) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 42160 + ... + 53457.

It is an arithmetic number, because the mean of its divisors is an integer number (51633720).

Almost surely, 2540140433 is an apocalyptic number.

It is an amenable number.

540140433 is a deficient number, since it is larger than the sum of its proper divisors (285999087).

540140433 is a wasteful number, since it uses less digits than its factorization.

540140433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 95896.

The product of its (nonzero) digits is 2880, while the sum is 24.

The square root of 540140433 is about 23240.9215178745. The cubic root of 540140433 is about 814.3958703061.

Adding to 540140433 its reverse (334041045), we get a palindrome (874181478).

The spelling of 540140433 in words is "five hundred forty million, one hundred forty thousand, four hundred thirty-three".

Divisors: 1 3 7 21 269 807 1883 5649 95617 286851 669319 2007957 25720973 77162919 180046811 540140433