Base | Representation |
---|---|
bin | 11000100110111010000100… |
… | …00000101110101111110001 |
3 | 21002121012010220210200221220 |
4 | 30103131002000232233301 |
5 | 24043043221003400113 |
6 | 311031204124335253 |
7 | 14253364336355211 |
oct | 1423350200565761 |
9 | 232535126720856 |
10 | 54113400450033 |
11 | 16273400903251 |
12 | 609b6583a4529 |
13 | 2426b4436b202 |
14 | d511615b4241 |
15 | 63c931508523 |
hex | 31374202ebf1 |
54113400450033 has 16 divisors (see below), whose sum is σ = 73682319029760. Its totient is φ = 35313185067264.
The previous prime is 54113400450007. The next prime is 54113400450089. The reversal of 54113400450033 is 33005400431145.
It is not a de Polignac number, because 54113400450033 - 222 = 54113396255729 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54113400449976 and 54113400450003.
It is not an unprimeable number, because it can be changed into a prime (54113400450533) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 392928673 + ... + 393066366.
It is an arithmetic number, because the mean of its divisors is an integer number (4605144939360).
Almost surely, 254113400450033 is an apocalyptic number.
54113400450033 is a gapful number since it is divisible by the number (53) formed by its first and last digit.
It is an amenable number.
54113400450033 is a deficient number, since it is larger than the sum of its proper divisors (19568918579727).
54113400450033 is a wasteful number, since it uses less digits than its factorization.
54113400450033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 785995528.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 54113400450033 its reverse (33005400431145), we get a palindrome (87118800881178).
The spelling of 54113400450033 in words is "fifty-four trillion, one hundred thirteen billion, four hundred million, four hundred fifty thousand, thirty-three".
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