Base | Representation |
---|---|
bin | 11000101101010001111000… |
… | …00010010001011100110001 |
3 | 21010101010021102211012112212 |
4 | 30112220330002101130301 |
5 | 24110140114420214441 |
6 | 311315533430301505 |
7 | 14305245056650436 |
oct | 1426507402213461 |
9 | 233333242735485 |
10 | 54332343523121 |
11 | 16348243528654 |
12 | 6115b7bab7895 |
13 | 24416970b5871 |
14 | d5b9b1451b8d |
15 | 643497a1eeeb |
hex | 316a3c091731 |
54332343523121 has 16 divisors (see below), whose sum is σ = 55105224819840. Its totient is φ = 53564537105280.
The previous prime is 54332343523103. The next prime is 54332343523177. The reversal of 54332343523121 is 12132534323345.
It is a cyclic number.
It is not a de Polignac number, because 54332343523121 - 214 = 54332343506737 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (54332343523321) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30288461 + ... + 32032101.
It is an arithmetic number, because the mean of its divisors is an integer number (3444076551240).
Almost surely, 254332343523121 is an apocalyptic number.
It is an amenable number.
54332343523121 is a deficient number, since it is larger than the sum of its proper divisors (772881296719).
54332343523121 is a wasteful number, since it uses less digits than its factorization.
54332343523121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1745096.
The product of its digits is 777600, while the sum is 41.
Adding to 54332343523121 its reverse (12132534323345), we get a palindrome (66464877846466).
The spelling of 54332343523121 in words is "fifty-four trillion, three hundred thirty-two billion, three hundred forty-three million, five hundred twenty-three thousand, one hundred twenty-one".
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