Base | Representation |
---|---|
bin | 111101111111000001110001… |
… | …1001100011110001110101010 |
3 | 2122111110220210202210200020020 |
4 | 1323332003203030132032222 |
5 | 1032430423014332333002 |
6 | 5211332302343141310 |
7 | 222562100314414236 |
oct | 17376034314361652 |
9 | 2574426722720206 |
10 | 545224140121002 |
11 | 1487a8294152821 |
12 | 51198111444836 |
13 | 1a52c55368b334 |
14 | 988cdbc4715c6 |
15 | 43077e772e2bc |
hex | 1efe0e331e3aa |
545224140121002 has 16 divisors (see below), whose sum is σ = 1105385927917440. Its totient is φ = 179251772094432.
The previous prime is 545224140120967. The next prime is 545224140121033. The reversal of 545224140121002 is 200121041422545.
It is a super-3 number, since 3×5452241401210023 (a number of 45 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 622401986002 + ... + 622401986877.
It is an arithmetic number, because the mean of its divisors is an integer number (69086620494840).
Almost surely, 2545224140121002 is an apocalyptic number.
545224140121002 is an abundant number, since it is smaller than the sum of its proper divisors (560161787796438).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
545224140121002 is a wasteful number, since it uses less digits than its factorization.
545224140121002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1244803972957.
The product of its (nonzero) digits is 25600, while the sum is 33.
Adding to 545224140121002 its reverse (200121041422545), we get a palindrome (745345181543547).
The spelling of 545224140121002 in words is "five hundred forty-five trillion, two hundred twenty-four billion, one hundred forty million, one hundred twenty-one thousand, two".
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