Base | Representation |
---|---|
bin | 10000000000101001000… |
… | …01011000111010011001 |
3 | 1221120220102102001100020 |
4 | 20000110201120322121 |
5 | 33003101112023001 |
6 | 1100413522301053 |
7 | 54512664536040 |
oct | 10002441307231 |
9 | 1846812361306 |
10 | 550100111001 |
11 | 1a2329198411 |
12 | 8a7434b7789 |
13 | 3cb4986c97c |
14 | 1c8a6d73557 |
15 | e4991a0736 |
hex | 8014858e99 |
550100111001 has 16 divisors (see below), whose sum is σ = 865288040448. Its totient is φ = 304202826000.
The previous prime is 550100110997. The next prime is 550100111081. The reversal of 550100111001 is 100111001055.
It is not a de Polignac number, because 550100111001 - 22 = 550100110997 is a prime.
It is a super-2 number, since 2×5501001110012 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (550100111081) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 422503275 + ... + 422504576.
It is an arithmetic number, because the mean of its divisors is an integer number (54080502528).
Almost surely, 2550100111001 is an apocalyptic number.
It is an amenable number.
550100111001 is a deficient number, since it is larger than the sum of its proper divisors (315187929447).
550100111001 is a wasteful number, since it uses less digits than its factorization.
550100111001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 845007892.
The product of its (nonzero) digits is 25, while the sum is 15.
Adding to 550100111001 its reverse (100111001055), we get a palindrome (650211112056).
The spelling of 550100111001 in words is "five hundred fifty billion, one hundred million, one hundred eleven thousand, one".
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