Base | Representation |
---|---|
bin | 10000000000110110010… |
… | …00011001100001010011 |
3 | 1221121012011001211000010 |
4 | 20000123020121201103 |
5 | 33003313004003103 |
6 | 1100432523130003 |
7 | 54515512223541 |
oct | 10003310314123 |
9 | 1847164054003 |
10 | 550211000403 |
11 | 1a2385847249 |
12 | 8a774673903 |
13 | 3cb66826abc |
14 | 1c8b799ad91 |
15 | e4a3ca6903 |
hex | 801b219853 |
550211000403 has 32 divisors (see below), whose sum is σ = 741544657920. Its totient is φ = 362869194240.
The previous prime is 550211000323. The next prime is 550211000483. The reversal of 550211000403 is 304000112055.
It is an interprime number because it is at equal distance from previous prime (550211000323) and next prime (550211000483).
It is not a de Polignac number, because 550211000403 - 28 = 550211000147 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 550211000403.
It is not an unprimeable number, because it can be changed into a prime (550211000483) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 89710125 + ... + 89716257.
It is an arithmetic number, because the mean of its divisors is an integer number (23173270560).
Almost surely, 2550211000403 is an apocalyptic number.
550211000403 is a deficient number, since it is larger than the sum of its proper divisors (191333657517).
550211000403 is a wasteful number, since it uses less digits than its factorization.
550211000403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7179.
The product of its (nonzero) digits is 600, while the sum is 21.
Adding to 550211000403 its reverse (304000112055), we get a palindrome (854211112458).
The spelling of 550211000403 in words is "five hundred fifty billion, two hundred eleven million, four hundred three", and thus it is an aban number.
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