Base | Representation |
---|---|
bin | 11001000011111110001110… |
… | …01110001111011110010001 |
3 | 21020010122212202120012002102 |
4 | 30201333013032033132101 |
5 | 24210424003322234403 |
6 | 313114045011130145 |
7 | 14415500262512342 |
oct | 1441770716173621 |
9 | 236118782505072 |
10 | 55112067774353 |
11 | 16618995543187 |
12 | 6221107ba3955 |
13 | 249a0794cac55 |
14 | d8761ca320c9 |
15 | 6588d0c77b88 |
hex | 321fc738f791 |
55112067774353 has 16 divisors (see below), whose sum is σ = 55408654366464. Its totient is φ = 54816226312320.
The previous prime is 55112067774349. The next prime is 55112067774359. The reversal of 55112067774353 is 35347776021155.
It is a cyclic number.
It is not a de Polignac number, because 55112067774353 - 22 = 55112067774349 is a prime.
It is a super-3 number, since 3×551120677743533 (a number of 42 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55112067774359) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 513347426 + ... + 513454772.
It is an arithmetic number, because the mean of its divisors is an integer number (3463040897904).
Almost surely, 255112067774353 is an apocalyptic number.
It is an amenable number.
55112067774353 is a deficient number, since it is larger than the sum of its proper divisors (296586592111).
55112067774353 is a wasteful number, since it uses less digits than its factorization.
55112067774353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110792.
The product of its (nonzero) digits is 18522000, while the sum is 56.
The spelling of 55112067774353 in words is "fifty-five trillion, one hundred twelve billion, sixty-seven million, seven hundred seventy-four thousand, three hundred fifty-three".
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