Base | Representation |
---|---|
bin | 101000010000000110101… |
… | …1100011010100101110001 |
3 | 201120212102120212021020011 |
4 | 1100200031130122211301 |
5 | 1211114312204230001 |
6 | 15433233121014521 |
7 | 1110453446166436 |
oct | 120401534324561 |
9 | 21525376767204 |
10 | 5532143430001 |
11 | 184319481a741 |
12 | 7541bb784441 |
13 | 3118a968cab6 |
14 | 151a85967b8d |
15 | 98d85223d51 |
hex | 5080d71a971 |
5532143430001 has 16 divisors (see below), whose sum is σ = 5780723397120. Its totient is φ = 5289212522880.
The previous prime is 5532143429959. The next prime is 5532143430041. The reversal of 5532143430001 is 1000343412355.
It is a cyclic number.
It is not a de Polignac number, because 5532143430001 - 219 = 5532142905713 is a prime.
It is a super-2 number, since 2×55321434300012 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5532143430041) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 384736 + ... + 3348478.
It is an arithmetic number, because the mean of its divisors is an integer number (361295212320).
Almost surely, 25532143430001 is an apocalyptic number.
It is an amenable number.
5532143430001 is a deficient number, since it is larger than the sum of its proper divisors (248579967119).
5532143430001 is a wasteful number, since it uses less digits than its factorization.
5532143430001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2964696.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 5532143430001 its reverse (1000343412355), we get a palindrome (6532486842356).
The spelling of 5532143430001 in words is "five trillion, five hundred thirty-two billion, one hundred forty-three million, four hundred thirty thousand, one".
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