Base | Representation |
---|---|
bin | 10000000110100000110… |
… | …00111011110000100011 |
3 | 1221220001002021011100211 |
4 | 20003100120323300203 |
5 | 33031030003323133 |
6 | 1102054354354551 |
7 | 54654046334014 |
oct | 10032030736043 |
9 | 1856032234324 |
10 | 553252011043 |
11 | 1a36a6378586 |
12 | 8b282b8ba57 |
13 | 4022c869b94 |
14 | 1cac57db00b |
15 | e5d0c4bbcd |
hex | 80d063bc23 |
553252011043 has 16 divisors (see below), whose sum is σ = 583828992000. Its totient is φ = 522821537280.
The previous prime is 553252010977. The next prime is 553252011047. The reversal of 553252011043 is 340110252355.
It is a cyclic number.
It is not a de Polignac number, because 553252011043 - 233 = 544662076451 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 553252010996 and 553252011014.
It is not an unprimeable number, because it can be changed into a prime (553252011047) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 42844758 + ... + 42857668.
It is an arithmetic number, because the mean of its divisors is an integer number (36489312000).
Almost surely, 2553252011043 is an apocalyptic number.
553252011043 is a deficient number, since it is larger than the sum of its proper divisors (30576980957).
553252011043 is a wasteful number, since it uses less digits than its factorization.
553252011043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18402.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 553252011043 its reverse (340110252355), we get a palindrome (893362263398).
The spelling of 553252011043 in words is "five hundred fifty-three billion, two hundred fifty-two million, eleven thousand, forty-three".
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