Base | Representation |
---|---|
bin | 101010101110100101010… |
… | …1011100110011000001001 |
3 | 202210101212202102202121211 |
4 | 1111131022223212120021 |
5 | 1232203311122041001 |
6 | 20253435453533121 |
7 | 1144162234625260 |
oct | 125351253463011 |
9 | 22711782382554 |
10 | 5872473237001 |
11 | 1964558057948 |
12 | 7aa15b4a41a1 |
13 | 337a059a6c17 |
14 | 16432cda95d7 |
15 | a2b53315351 |
hex | 5574aae6609 |
5872473237001 has 16 divisors (see below), whose sum is σ = 6887659524480. Its totient is φ = 4901801224320.
The previous prime is 5872473236983. The next prime is 5872473237023. The reversal of 5872473237001 is 1007323742785.
It is not a de Polignac number, because 5872473237001 - 25 = 5872473236969 is a prime.
It is a super-3 number, since 3×58724732370013 (a number of 39 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (5872473237101) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18546466 + ... + 18860443.
It is an arithmetic number, because the mean of its divisors is an integer number (430478720280).
Almost surely, 25872473237001 is an apocalyptic number.
It is an amenable number.
5872473237001 is a deficient number, since it is larger than the sum of its proper divisors (1015186287479).
5872473237001 is a wasteful number, since it uses less digits than its factorization.
5872473237001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37407504.
The product of its (nonzero) digits is 1975680, while the sum is 49.
Adding to 5872473237001 its reverse (1007323742785), we get a palindrome (6879796979786).
The spelling of 5872473237001 in words is "five trillion, eight hundred seventy-two billion, four hundred seventy-three million, two hundred thirty-seven thousand, one".
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