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6010134113 = 791574211151
BaseRepresentation
bin1011001100011101…
…10101111001100001
3120111212010110001202
411212032311321201
544302043242423
62432214010545
7301636203614
oct54616657141
916455113052
106010134113
112604622795
1211b8946a55
1374a206699
144102ca17b
1525298a728
hex1663b5e61

6010134113 has 16 divisors (see below), whose sum is σ = 6144860160. Its totient is φ = 5877144000.

The previous prime is 6010134103. The next prime is 6010134211. The reversal of 6010134113 is 3114310106.

It is a cyclic number.

It is not a de Polignac number, because 6010134113 - 216 = 6010068577 is a prime.

It is a super-2 number, since 2×60101341132 = 72243424112492593538, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (6010134103) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5221088 + ... + 5222238.

It is an arithmetic number, because the mean of its divisors is an integer number (384053760).

Almost surely, 26010134113 is an apocalyptic number.

It is an amenable number.

6010134113 is a deficient number, since it is larger than the sum of its proper divisors (134726047).

6010134113 is a wasteful number, since it uses less digits than its factorization.

6010134113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1808.

The product of its (nonzero) digits is 216, while the sum is 20.

The square root of 6010134113 is about 77525.0547436118. The cubic root of 6010134113 is about 1818.1430676895.

Adding to 6010134113 its reverse (3114310106), we get a palindrome (9124444219).

The spelling of 6010134113 in words is "six billion, ten million, one hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 79 157 421 1151 12403 33259 66097 90929 180707 484571 5221663 14275853 38281109 76077647 6010134113