Base | Representation |
---|---|
bin | 101011110000010111100… |
… | …0010001110000011011001 |
3 | 210021220112010000211010010 |
4 | 1113200233002032003121 |
5 | 1242012121242403101 |
6 | 20442401530112133 |
7 | 1160323110565230 |
oct | 127405702160331 |
9 | 23256463024103 |
10 | 6013743325401 |
11 | 1a09461369219 |
12 | 81160657b649 |
13 | 34812a7301c6 |
14 | 16b0d116db17 |
15 | a66707b92d6 |
hex | 5782f08e0d9 |
6013743325401 has 16 divisors (see below), whose sum is σ = 9175841163648. Its totient is φ = 3431909078400.
The previous prime is 6013743325357. The next prime is 6013743325451. The reversal of 6013743325401 is 1045233473106.
It is not a de Polignac number, because 6013743325401 - 213 = 6013743317209 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 6013743325401.
It is not an unprimeable number, because it can be changed into a prime (6013743325451) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 188136930 + ... + 188168891.
It is an arithmetic number, because the mean of its divisors is an integer number (573490072728).
Almost surely, 26013743325401 is an apocalyptic number.
It is an amenable number.
6013743325401 is a deficient number, since it is larger than the sum of its proper divisors (3162097838247).
6013743325401 is a wasteful number, since it uses less digits than its factorization.
6013743325401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 376306592.
The product of its (nonzero) digits is 181440, while the sum is 39.
Adding to 6013743325401 its reverse (1045233473106), we get a palindrome (7058976798507).
The spelling of 6013743325401 in words is "six trillion, thirteen billion, seven hundred forty-three million, three hundred twenty-five thousand, four hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •