Base | Representation |
---|---|
bin | 11011110111011111100101… |
… | …10111000111001001110011 |
3 | 22000222100100112222022000210 |
4 | 31323233302313013021303 |
5 | 31013004200433224043 |
6 | 334155451550115203 |
7 | 15623234524415004 |
oct | 1573576267071163 |
9 | 260870315868023 |
10 | 61280372945523 |
11 | 18586950a51816 |
12 | 6a58668aabb03 |
13 | 2826939629214 |
14 | 111bdb335b1ab |
15 | 71409a879633 |
hex | 37bbf2dc7273 |
61280372945523 has 16 divisors (see below), whose sum is σ = 82502567746560. Its totient is φ = 40455900538944.
The previous prime is 61280372945521. The next prime is 61280372945537. The reversal of 61280372945523 is 32554927308216.
It is not a de Polignac number, because 61280372945523 - 21 = 61280372945521 is a prime.
It is not an unprimeable number, because it can be changed into a prime (61280372945521) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9517063 + ... + 14599151.
It is an arithmetic number, because the mean of its divisors is an integer number (5156410484160).
It is a 1-persistent number, because it is pandigital, but 2⋅61280372945523 = 122560745891046 is not.
Almost surely, 261280372945523 is an apocalyptic number.
61280372945523 is a deficient number, since it is larger than the sum of its proper divisors (21222194801037).
61280372945523 is a wasteful number, since it uses less digits than its factorization.
61280372945523 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5121218.
The product of its (nonzero) digits is 21772800, while the sum is 57.
The spelling of 61280372945523 in words is "sixty-one trillion, two hundred eighty billion, three hundred seventy-two million, nine hundred forty-five thousand, five hundred twenty-three".
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