Base | Representation |
---|---|
bin | 11011111011011110100010… |
… | …11000011001101110000011 |
3 | 22001110102122202200021212002 |
4 | 31331233101120121232003 |
5 | 31022230012022403301 |
6 | 334342410100454215 |
7 | 15636151500035165 |
oct | 1575572130315603 |
9 | 261412582607762 |
10 | 61417250200451 |
11 | 18629a00659302 |
12 | 6a7b0a89aa36b |
13 | 283681125b462 |
14 | 1124879d50935 |
15 | 71790c35d16b |
hex | 37dbd1619b83 |
61417250200451 has 16 divisors (see below), whose sum is σ = 61576983665280. Its totient is φ = 61257752973120.
The previous prime is 61417250200399. The next prime is 61417250200463. The reversal of 61417250200451 is 15400205271416.
It is a cyclic number.
It is not a de Polignac number, because 61417250200451 - 238 = 61142372293507 is a prime.
It is a super-3 number, since 3×614172502004513 (a number of 42 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (61417250200351) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3372526736 + ... + 3372544946.
It is an arithmetic number, because the mean of its divisors is an integer number (3848561479080).
Almost surely, 261417250200451 is an apocalyptic number.
61417250200451 is a deficient number, since it is larger than the sum of its proper divisors (159733464829).
61417250200451 is a wasteful number, since it uses less digits than its factorization.
61417250200451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24226.
The product of its (nonzero) digits is 67200, while the sum is 38.
Adding to 61417250200451 its reverse (15400205271416), we get a palindrome (76817455471867).
The spelling of 61417250200451 in words is "sixty-one trillion, four hundred seventeen billion, two hundred fifty million, two hundred thousand, four hundred fifty-one".
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