Base | Representation |
---|---|
bin | 11101010011010010101100… |
… | …01110111100000111001001 |
3 | 22110010212211022021220011101 |
4 | 32221221112032330013021 |
5 | 31421143422302201101 |
6 | 345012453304101401 |
7 | 16400146056215035 |
oct | 1651512616740711 |
9 | 273125738256141 |
10 | 64434546131401 |
11 | 195925a0538996 |
12 | 7287a1b164861 |
13 | 29c51c8186414 |
14 | 11ca911d5b1c5 |
15 | 76b155232401 |
hex | 3a9a563bc1c9 |
64434546131401 has 16 divisors (see below), whose sum is σ = 65540247887808. Its totient is φ = 63330453288000.
The previous prime is 64434546131377. The next prime is 64434546131429. The reversal of 64434546131401 is 10413164543446.
It is a cyclic number.
It is not a de Polignac number, because 64434546131401 - 27 = 64434546131273 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (64434546131801) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 527213566 + ... + 527335768.
It is an arithmetic number, because the mean of its divisors is an integer number (4096265492988).
Almost surely, 264434546131401 is an apocalyptic number.
64434546131401 is a gapful number since it is divisible by the number (61) formed by its first and last digit.
It is an amenable number.
64434546131401 is a deficient number, since it is larger than the sum of its proper divisors (1105701756407).
64434546131401 is a wasteful number, since it uses less digits than its factorization.
64434546131401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 128712.
The product of its (nonzero) digits is 1658880, while the sum is 46.
The spelling of 64434546131401 in words is "sixty-four trillion, four hundred thirty-four billion, five hundred forty-six million, one hundred thirty-one thousand, four hundred one".
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