Base | Representation |
---|---|
bin | 11101101001111101111011… |
… | …00000110011010111100011 |
3 | 22112220100212122110000202020 |
4 | 32310332331200303113203 |
5 | 32021430042443314003 |
6 | 350410425004352523 |
7 | 16510350325330521 |
oct | 1664767540632743 |
9 | 275810778400666 |
10 | 65213667948003 |
11 | 19862a63492463 |
12 | 7392a19545743 |
13 | 2a5081282ca03 |
14 | 121650351d311 |
15 | 78155563ad53 |
hex | 3b4fbd8335e3 |
65213667948003 has 16 divisors (see below), whose sum is σ = 87348721022976. Its totient is φ = 43277229103680.
The previous prime is 65213667947999. The next prime is 65213667948019. The reversal of 65213667948003 is 30084976631256.
It is a Cunningham number, because it is equal to 80754982-1.
It is not a de Polignac number, because 65213667948003 - 22 = 65213667947999 is a prime.
It is not an unprimeable number, because it can be changed into a prime (65213667943003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4037751 + ... + 12113247.
It is an arithmetic number, because the mean of its divisors is an integer number (5459295063936).
It is a 2-persistent number, because it is pandigital, and so is 2⋅65213667948003 = 130427335896006, but 3⋅65213667948003 = 195641003844009 is not.
Almost surely, 265213667948003 is an apocalyptic number.
65213667948003 is a deficient number, since it is larger than the sum of its proper divisors (22135053074973).
65213667948003 is a wasteful number, since it uses less digits than its factorization.
65213667948003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8087794.
The product of its (nonzero) digits is 39191040, while the sum is 60.
The spelling of 65213667948003 in words is "sixty-five trillion, two hundred thirteen billion, six hundred sixty-seven million, nine hundred forty-eight thousand, three".
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