Base | Representation |
---|---|
bin | 11100110100100110100… |
… | …10010010101010000011 |
3 | 10111200011122121110012212 |
4 | 32122103102102222003 |
5 | 112211130230230333 |
6 | 2034535503412335 |
7 | 131355615030530 |
oct | 16322322225203 |
9 | 3450148543185 |
10 | 990313523843 |
11 | 351a98191aa6 |
12 | 13bb19bb40ab |
13 | 72503532947 |
14 | 35d07bb7d87 |
15 | 1ab61189448 |
hex | e693492a83 |
990313523843 has 16 divisors (see below), whose sum is σ = 1137926929920. Its totient is φ = 844245567936.
The previous prime is 990313523827. The next prime is 990313523869. The reversal of 990313523843 is 348325313099.
It is a cyclic number.
It is not a de Polignac number, because 990313523843 - 24 = 990313523827 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 990313523791 and 990313523800.
It is not an unprimeable number, because it can be changed into a prime (990313523803) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 705071 + ... + 1574087.
It is an arithmetic number, because the mean of its divisors is an integer number (71120433120).
Almost surely, 2990313523843 is an apocalyptic number.
990313523843 is a deficient number, since it is larger than the sum of its proper divisors (147613406077).
990313523843 is a wasteful number, since it uses less digits than its factorization.
990313523843 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 869906.
The product of its (nonzero) digits is 2099520, while the sum is 50.
The spelling of 990313523843 in words is "nine hundred ninety billion, three hundred thirteen million, five hundred twenty-three thousand, eight hundred forty-three".
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