100000013003233 has 4 divisors (see below), whose sum is σ = 114285729146560. Its totient is φ = 85714296859908.

The previous prime is 100000013003179. The next prime is 100000013003249. The reversal of 100000013003233 is 332300310000001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100000013003233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100000013003333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7142858071653 + ... + 7142858071666.

It is an arithmetic number, because the mean of its divisors is an integer number (28571432286640).

Almost surely, 2^{100000013003233} is an apocalyptic number.

It is an amenable number.

100000013003233 is a deficient number, since it is larger than the sum of its proper divisors (14285716143327).

100000013003233 is an equidigital number, since it uses as much as digits as its factorization.

100000013003233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14285716143326.

The product of its (nonzero) digits is 162, while the sum is 16.

Adding to 100000013003233 its reverse (332300310000001), we get a palindrome (432300323003234).

The spelling of 100000013003233 in words is "one hundred trillion, thirteen million, three thousand, two hundred thirty-three".