1000101000113 has 4 divisors (see below), whose sum is σ = 1000105581300. Its totient is φ = 1000096418928.

The previous prime is 1000101000061. The next prime is 1000101000139. The reversal of 1000101000113 is 3110001010001.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 163849277089 + 836251723024 = 404783^2 + 914468^2 .

It is a cyclic number.

It is not a de Polignac number, because 1000101000113 - 2⁸ = 1000100999857 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1000101000113.

It is not an unprimeable number, because it can be changed into a prime (1000101000313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1945838 + ... + 2405511.

It is an arithmetic number, because the mean of its divisors is an integer number (250026395325).

Almost surely, 2^{1000101000113} is an apocalyptic number.

It is an amenable number.

1000101000113 is a deficient number, since it is larger than the sum of its proper divisors (4581187).

1000101000113 is an equidigital number, since it uses as much as digits as its factorization.

1000101000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4581186.

The product of its (nonzero) digits is 3, while the sum is 8.

Adding to 1000101000113 its reverse (3110001010001), we get a palindrome (4110102010114).

The spelling of 1000101000113 in words is "one trillion, one hundred one million, one hundred thirteen", and thus it is an aban number.