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100011023113 = 1078871053757
BaseRepresentation
bin101110100100100011…
…1110001101100001001
3100120010221101101010011
41131021013301230021
53114310310214423
6113535555151521
710140236445601
oct1351107615411
9316127341104
10100011023113
1139461684a11
12174715a55a1
13957ab9bbb1
144baa6cdc01
1529051b5b0d
hex17491f1b09

100011023113 has 8 divisors (see below), whose sum is σ = 101059607232. Its totient is φ = 98964548496.

The previous prime is 100011023087. The next prime is 100011023131. The reversal of 100011023113 is 311320110001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 100011023113 - 229 = 99474152201 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100011023093 and 100011023102.

It is not an unprimeable number, because it can be changed into a prime (100011023173) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 431970 + ... + 621787.

It is an arithmetic number, because the mean of its divisors is an integer number (12632450904).

Almost surely, 2100011023113 is an apocalyptic number.

It is an amenable number.

100011023113 is a deficient number, since it is larger than the sum of its proper divisors (1048584119).

100011023113 is a wasteful number, since it uses less digits than its factorization.

100011023113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1054751.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 100011023113 its reverse (311320110001), we get a palindrome (411331133114).

The spelling of 100011023113 in words is "one hundred billion, eleven million, twenty-three thousand, one hundred thirteen".

Divisors: 1 107 887 94909 1053757 112751999 934682459 100011023113