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100011104115 = 3513512877457
BaseRepresentation
bin101110100100100100…
…0000101011101110011
3100120010221112111020020
41131021020011131303
53114310320312430
6113540001014523
710140240234006
oct1351110053563
9316127474206
10100011104115
113946172a85a
1217471624443
13957abc9a20
144baa71153d
1529051ceb10
hex1749205773

100011104115 has 16 divisors (see below), whose sum is σ = 172326825888. Its totient is φ = 49236235776.

The previous prime is 100011104113. The next prime is 100011104161. The reversal of 100011104115 is 511401110001.

It is not a de Polignac number, because 100011104115 - 21 = 100011104113 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a junction number, because it is equal to n+sod(n) for n = 100011104094 and 100011104103.

It is not an unprimeable number, because it can be changed into a prime (100011104111) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 256438534 + ... + 256438923.

It is an arithmetic number, because the mean of its divisors is an integer number (10770426618).

Almost surely, 2100011104115 is an apocalyptic number.

100011104115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

100011104115 is a deficient number, since it is larger than the sum of its proper divisors (72315721773).

100011104115 is a wasteful number, since it uses less digits than its factorization.

100011104115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 512877478.

The product of its (nonzero) digits is 20, while the sum is 15.

Adding to 100011104115 its reverse (511401110001), we get a palindrome (611412214116).

The spelling of 100011104115 in words is "one hundred billion, eleven million, one hundred four thousand, one hundred fifteen".

Divisors: 1 3 5 13 15 39 65 195 512877457 1538632371 2564387285 6667406941 7693161855 20002220823 33337034705 100011104115