Base | Representation |
---|---|
bin | 101110100100100100… |
… | …0000101011101110011 |
3 | 100120010221112111020020 |
4 | 1131021020011131303 |
5 | 3114310320312430 |
6 | 113540001014523 |
7 | 10140240234006 |
oct | 1351110053563 |
9 | 316127474206 |
10 | 100011104115 |
11 | 3946172a85a |
12 | 17471624443 |
13 | 957abc9a20 |
14 | 4baa71153d |
15 | 29051ceb10 |
hex | 1749205773 |
100011104115 has 16 divisors (see below), whose sum is σ = 172326825888. Its totient is φ = 49236235776.
The previous prime is 100011104113. The next prime is 100011104161. The reversal of 100011104115 is 511401110001.
It is not a de Polignac number, because 100011104115 - 21 = 100011104113 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a junction number, because it is equal to n+sod(n) for n = 100011104094 and 100011104103.
It is not an unprimeable number, because it can be changed into a prime (100011104111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 256438534 + ... + 256438923.
It is an arithmetic number, because the mean of its divisors is an integer number (10770426618).
Almost surely, 2100011104115 is an apocalyptic number.
100011104115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
100011104115 is a deficient number, since it is larger than the sum of its proper divisors (72315721773).
100011104115 is a wasteful number, since it uses less digits than its factorization.
100011104115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 512877478.
The product of its (nonzero) digits is 20, while the sum is 15.
Adding to 100011104115 its reverse (511401110001), we get a palindrome (611412214116).
The spelling of 100011104115 in words is "one hundred billion, eleven million, one hundred four thousand, one hundred fifteen".
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