100011133011313 has 4 divisors (see below), whose sum is σ = 100289715554880. Its totient is φ = 99732550467748.

The previous prime is 100011133011301. The next prime is 100011133011323. The reversal of 100011133011313 is 313110331110001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100011133011313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100011133011323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139291271245 + ... + 139291271962.

It is an arithmetic number, because the mean of its divisors is an integer number (25072428888720).

Almost surely, 2^{100011133011313} is an apocalyptic number.

It is an amenable number.

100011133011313 is a deficient number, since it is larger than the sum of its proper divisors (278582543567).

100011133011313 is an equidigital number, since it uses as much as digits as its factorization.

100011133011313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 278582543566.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 100011133011313 its reverse (313110331110001), we get a palindrome (413121464121314).

The spelling of 100011133011313 in words is "one hundred trillion, eleven billion, one hundred thirty-three million, eleven thousand, three hundred thirteen".