1000113131233 has 4 divisors (see below), whose sum is σ = 1000118160580. Its totient is φ = 1000108101888.

The previous prime is 1000113131221. The next prime is 1000113131249. The reversal of 1000113131233 is 3321313110001.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 298041748624 + 702071382609 = 545932^2 + 837897^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1000113131233 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1000113131233.

It is not an unprimeable number, because it can be changed into a prime (1000113131833) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2203560 + ... + 2618377.

It is an arithmetic number, because the mean of its divisors is an integer number (250029540145).

Almost surely, 2^{1000113131233} is an apocalyptic number.

It is an amenable number.

1000113131233 is a deficient number, since it is larger than the sum of its proper divisors (5029347).

1000113131233 is an equidigital number, since it uses as much as digits as its factorization.

1000113131233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5029346.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1000113131233 its reverse (3321313110001), we get a palindrome (4321426241234).

The spelling of 1000113131233 in words is "one trillion, one hundred thirteen million, one hundred thirty-one thousand, two hundred thirty-three".