Search a number
-
+
100012033113 = 3291149563599
BaseRepresentation
bin101110100100100101…
…1101000010001011001
3100120011000021200120120
41131021023220101121
53114311040024423
6113540032543453
710140251153316
oct1351113502131
9316130250516
10100012033113
1139462204823
12174719b1b89
13957b163825
144baa8b3d0d
152905314ee3
hex17492e8459

100012033113 has 8 divisors (see below), whose sum is σ = 137947632000. Its totient is φ = 64375561488.

The previous prime is 100012033111. The next prime is 100012033157. The reversal of 100012033113 is 311330210001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 100012033113 - 21 = 100012033111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100012033092 and 100012033101.

It is not an unprimeable number, because it can be changed into a prime (100012033111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 574781713 + ... + 574781886.

It is an arithmetic number, because the mean of its divisors is an integer number (17243454000).

Almost surely, 2100012033113 is an apocalyptic number.

It is an amenable number.

100012033113 is a deficient number, since it is larger than the sum of its proper divisors (37935598887).

100012033113 is a wasteful number, since it uses less digits than its factorization.

100012033113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1149563631.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 100012033113 its reverse (311330210001), we get a palindrome (411342243114).

The spelling of 100012033113 in words is "one hundred billion, twelve million, thirty-three thousand, one hundred thirteen".

Divisors: 1 3 29 87 1149563599 3448690797 33337344371 100012033113