100012110313 has 4 divisors (see below), whose sum is σ = 100014520320. Its totient is φ = 100009700308.

The previous prime is 100012110307. The next prime is 100012110343. The reversal of 100012110313 is 313011210001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100012110313 - 2²⁵ = 99978555881 is a prime.

It is a super-3 number, since 3×100012110313³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100012110293 and 100012110302.

It is not an unprimeable number, because it can be changed into a prime (100012110343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1141645 + ... + 1226122.

It is an arithmetic number, because the mean of its divisors is an integer number (25003630080).

Almost surely, 2^100012110313 is an apocalyptic number.

It is an amenable number.

100012110313 is a deficient number, since it is larger than the sum of its proper divisors (2410007).

100012110313 is an equidigital number, since it uses as much as digits as its factorization.

100012110313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2410006.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 100012110313 its reverse (313011210001), we get a palindrome (413023320314).

The spelling of 100012110313 in words is "one hundred billion, twelve million, one hundred ten thousand, three hundred thirteen".